One thing you may find helpful is to first change any subtraction to the addition of a negative number. This can help avoid losing the negative.
To solve for the variable \({\text{x}}\) we use the order of operations backwards, but first, let’s find our steps going forward through the order of operations assuming we had a specific number for \({\text{x}}\).
If we were going forward, our steps would go as follows:
- Parentheses: None this time
- Exponents: None this time
- Multiplication & Division: between the \(\left (\frac{-2}{3} \right )\) and \({\text{x}}\) so, first multiply the \(\left (\frac{-2}{3} \right ){\text{x}}\)
- Addition & subtraction: Add \(\frac{1}{3}\) to our previous answer.
Going backwards to solve for a variable:
Since we are solving for a variable, we do these steps in reverse.
Step 1: Do the reverse of adding \(\frac{1}{3}\) to each side of the equation. In other words, subtract \(\frac{1}{3}\) from each side or add a negative \(\frac{1}{3}\) to each side.
On the left-hand side:
The additive inverses \(\frac{-1}{3}\) and \(\frac{+1}{3}\) add together to \(0\). This leaves just \(\left (\frac{-2}{3} \right ){\text{x}}\) on the left side.
On the right-hand side:
We have \(3+\left ( \frac{-1}{3} \right )\)
Adding fractions requires common denominators. The number 3 is a whole number, so it has an invisible denominator of 1. We can rewrite it as \(\frac{3}{1}\).
The greatest common denominator between 1 and 3 is 3. Multiply \(\frac{3}{1}\) by \(\frac{3}{3}\) to get the common denominator 3.
When adding or subtracting fractions with common denominators, we simply add or subtract the numbers in the numerator. The denominator stays the same because that is the part of the fraction that tells us what sizes the pieces are.
\(\left ( \frac{9}{3} \right )+\left ( \frac{-1}{3} \right )=\frac{8}{3}\)
We subtract \(9-1\). The negative on the \(\left ( \frac{1}{3} \right )\) is the same as adding a negative 1 or subtracting 1.
This leaves us with \(\left ( \frac{-2}{3} \right ){\text{x}}\) on the left and \(\frac{8}{3}\) on the right.
Step 2: Multiply both sides by the multiplicative inverse of \(\frac{-2}{3}\).
This will leave just \(1{\text{x}}\) on the left-hand side.
\(-\frac{24}{6}=-4\)
Our final solution: \({\text{x}} = -4\)